a^2+a^2=3600

Solution for a^2+a^2=3600 equation:

a^2+a^2=3600

We move all terms to the left:

a^2+a^2-(3600)=0

We add all the numbers together, and all the variables

2a^2-3600=0

a = 2; b = 0; c = -3600;
Δ = b2-4ac
Δ = 02-4·2·(-3600)
Δ = 28800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28800}=\sqrt{14400*2}=\sqrt{14400}*\sqrt{2}=120\sqrt{2}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120\sqrt{2}}{2*2}=\frac{0-120\sqrt{2}}{4}
=-\frac{120\sqrt{2}}{4}
=-30\sqrt{2}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120\sqrt{2}}{2*2}=\frac{0+120\sqrt{2}}{4}
=\frac{120\sqrt{2}}{4}
=30\sqrt{2}
$